The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass? The equation for the speed of a satellite in a circular orbit around …

Question

asked Jul 12, 2020 62.0k views

1 Answer

Sjrd · Answer 1 · 2020-07-17T07:17:18+0000

Answer:

$v=\sqrt{(G.M_c)/(R) }$

M_c= mass of the earth.

Step-by-step explanation:

During the revolution of a satellite around a central mass of heavenly body:

$\rm Centripetal\ force\ on\ satellite = Gravitational\ force\ on\ the\ satellite\ due\ to\ the\ central\ heavenly\ mass\$

F_c=F_G

M_s.(v^2)/(R) =G.(M_s.M_c)/(R^2)

where:

G = gravitational constant

R = radius of the orbit

$M_s\ \&\ M_c=$ mass of satellite and mass of central heavenly body (here we've the Earth)

v = orbital speed of the satellite

$\Rightarrow v^2=G.(M_c)/(R)$

$v=\sqrt{(G.M_c)/(R) }$