Question

When an RL circuit is connected to a battery, which is true about its initial and final states?

A. It initially acts like a broken wire and finally acts like ordinary connecting wire.
B. It initially acts like ordinary connecting wire and finally acts like a broken wire.
C. It acts like broken wire throughout the charging.
D. It acts like ordinary connecting wire throughout the charging.

Answer 1

Answer:A

Step-by-step explanation:

In R-L circuit current is given by

`i=i_0\left [ 1-e^{(-t)/(L/R)}\right ]`

where i=current at any time t

`i_0=maximum\ current`

R=resistance

L=Inductance

at t=0
`e^{(-t)/(L/R)}` approaches to 1

therefore
`i=i_0\left [ 1-1\right ]`

i=0

when t approaches to
`\infty`,
`e^{(-t)/(L/R)}` approaches to zero

thus
`i=i_0`

thus we can say that initially circuit act as broken wire with zero current

and it increases exponentially with time and act as ordinary connecting wire