Question

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Eloise started to solve a radical equation in this way:

square root of negative 2x plus 1 − 3 = x
square root of negative 2x plus 1 − 3 + 3 = x + 3
square root of negative 2x plus 1 = x + 3
square root of negative 2x plus 1 − 1 = x + 3 − 1
square root of negative 2 x = x + 2
(square root of negative 2 x)2 = (x − 4)2
−2x = x2 − 8x + 16
−2x + 2x = x2 + 8x + 16 + 2x
0 = x2 + 10x + 16
0 = (x + 2)(x + 8)

x + 2 = 0 x + 8 = 0
x + 2 − 2 = 0 − 2 x + 8 − 8 = 0 − 8
x = −2 x = −8

Both solutions are extraneous because they don't satisfy the original equation.

What error did Eloise make?

A, She added 2x after squaring both sides.
B, She subtracted 1 before squaring both sides.
C, She factored x2 + 10x + 16 incorrectly.
D, She did not check for extraneous solutions.

Answer 1

Answer: the correct answer is She subtracted 1 before squaring both sides

Step-by-step explanation: I got it wrong and this was the right answer