Question

Can you guys help me find the cosine of both angle A and angle B?

Answer 1

see explanation

Explanation:

cosA =
`(adjacent)/(hypotenuse)` =
`(24)/(26)` =
`(12)/(13)`

cosB =
`(adjacent)/(hypotenuse)` =
`(10)/(26)` =
`(5)/(13)`

Answer 2

`\displaystyle (5)/(13) = cos∠B \\ (12)/(13) = cos∠A`

Step-by-step explanation:

`\displaystyle (OPPOSITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOSITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOSITE) = csc\:θ \\ (ADJACENT)/(OPPOSITE) = cot\:θ \\ \\ (10)/(26) = cos∠B → (5)/(13) = cos∠B \\ \\ (24)/(26) = cos∠A → (12)/(13) = cos∠A`

I am joyous to assist you anytime.