Question

What is the awnser to the circled equations?​

Answer 1

`y = - (1)/(3)x - 1`

Explanation:

We have to write an equation of a line which passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)

Now, equation (1) is in the slope-intercept form and the slope of the line is 3.

Let, m is the slope of the required line.

So, 3m = -1

{Since, the product of the slopes of two perpendicular straight lines is -1}

⇒
`m = - (1)/(3)`

Therefore, the equation of the required line in slope intercept form is

`y = - (1)/(3) x + c` {Where c is a constant}

Now, this above equation passes through the point (-9,2) point.

So,
`2 = -  (1)/(3) * (-9) + c`

⇒ 2 = 3 + c

⇒ c = - 1

Therefore, the equation of the required straight line is
`y = - (1)/(3)x - 1` (Answer)