Question

A vertical spring withk= 245N/m oscillates with an amplitude of 19.2cm when 0.457kg hangs from it. The mass posses through the equilibrium point (y= 0) with a negative velocity at t= 0.Assume that downward is the positive direction of motion. What equation describes this motion as a function of time?

Answer 1

y = -19.2 sin (23.15t) cm

Step-by-step explanation:

The spring mass system is an oscillatory movement that is described by the equation

y = yo cos (wt + φ)

Let's look for the terms of this equation the amplitude I

y₀ = 19.2 cm

Angular velocity is

w = √ (k / m)

w = √ (245 / 0.457

w = 23.15 rad / s

The φ phase is determined for the initial condition t = 0 s , the velocity is negative v (0) = -vo

The speed of the equation is obtained by the derivative with respect to time

v = dy / dt

v = - y₀ w sin (wt + φ)

For t = 0

-vo = -yo w sin φ

The angular and linear velocity are related v = w r

v₀ = w r₀

v₀ = v₀ sinφ

sinφ = 1

φ = sin⁻¹ 1

φ = π / 4 rad

Let's build the equation

y = 19.2 cos (23.15 t + π/ 4)

Let's use the trigonometric ratio π/ 4 = 90º

Cos (a +90) = cos a cos90 - sin a sin sin 90 = 0 - sin a

y = -19.2 sin (23.15t) cm