Question

Explain: If measurements of a gas are 100 ml and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe what had to happen to the pressure of the temperature remained constant. Include which law supports this observation.

Answer 1

The pressure decreases to 0.4 kilopascals.

Step-by-step explanation:

Given:

Initial volume of the gas is,
`V_1=100\ ml=(100)/(1000)\ L=0.1\ L`

Final volume of the gas is,
`V_2=75\ L`

Initial pressure of the gas is,
`P_1=300\ kPa`

Final pressure of the gas is,
`P_2=?`

The temperature is constant (isothermal) for the given process.

We know that for a process of constant temperature, pressure of a gas varies inversely with volume. This fact is known as Boyle's Law. So, as per Boyle's Law, the product of pressure and volume of a gas undergoing isothermal process is a constant. Therefore,

`P_1V_1=P_2V_2\\300* 0.1=P_2* 75\\30=75P_2\\P_2=(30)/(75)=0.4\ kPa`

Therefore, the pressure of the gas gets reduced to a value of 0.4 kPa.