Question

If 3.0 g of NH3 reacts with 5.0 g of HCl, what is the limiting reactant?

Answer 1

Answer:HCl

Step-by-step explanation:

`\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}`

For
`NH_(3),`

`\text{given mass}=3g`

`\text{molar mass}=14+3=17g`

`n_{NH_(3)}=(3)/(17)=0.176`

For
`HCl,`

`\text{given mass}=5g`

`\text{molar mass}=1+35.5=36.5g`

`n_(HCl)=(5)/(36.5)=0.136`

The reaction between
`NH_(3)` and
`HCl` is

`NH_(3)+HCl`→
`NH_(4)Cl`

So,one mole of
`NH_(3)` requires one mole of
`HCl`

`0.176` moles of
`NH_(3)` requires
`0.176` moles of
`HCl`

But there are only
`0.136` moles of
`HCl` available.

`HCl` will be consumed first.

So,
`HCl` is the limiting reagent.