Question

Plz help :(

Write the equation for the dissolution of Sr(N03)2 in water. How many moles of strontium ions and nitrate ions are produced by dissolving 0.5 mol of strontium nitrate?

Answer 1

Answer:0.5 moles,1 mole

Step-by-step explanation:

`Sr(NO_(3))_(2)` is readily soluble in water.

`Sr(NO_(3))_(2)` dissolves in water to give
`Sr^(2+)` ions and
`NO_(3)^(-)` ions.

The reaction is

`Sr(NO_(3))_(2)`→
`Sr^(2+)`
`+2NO_(3)^(-)`

So,
`1` mole of
`Sr(NO_(3))_(2)` gives
`1` mole of
`Sr^(2+)` and
`2` moles of
`NO_(3)^(-)`.

So,
`0.5` moles of
`Sr(NO_(3))_(2)` gives
`0.5` moles of
`Sr^(2+)` and
`1` mole of
`NO_(3)^(-)`.