Question

Which function could this graph represent?

O y=2sin x+2
O y=-2sin x+ 2
O y= 2cos x + 2
O y=-2cos x + 2

Answer 1

y = -2sin(x) + 2

Explanation:

The sin(x) function is zero at x=0, so you want a sine function of some sort. The slope of your graph at x=0 is negative so you want a sine function with a negative multiplier. The appropriate choice is the one shown above.

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The cos(x) function is 1 at x=0, so any graph involving the cosine will not go through the point (0, 2) the way your graph does.