Question

Suppose your bicycle tire is fully inflated, with an absolute pressure of 7.00×105 Pa at a temperature of 21 °C. What is the pressure after its temperature has risen to 35.0ºC ? Assume that there are no appreciable leaks or changes in volume. Hint: At first, it may seem that not enough information is given, because the volume V and number of moles n are not specified. What we can do is use the equation twice: P0 V0 = nRT0 Pf Vf = nRTf . If we divide Pf Vf by P0 V0 we can come up with an equation that allows us to solve for Pf . Report the pressure in 105 Pa. For example, if the pressure is 7.36*105 Pa, just enter 7.36.

Answer 1

`P_2 = 7.33 * 10^5 Pa`

Step-by-step explanation:

As we know that the tyre is fully inflated

So here we can say that the volume will remain constant

So we have

`(P_1)/(T_1) = (P_2)/(T_2)`

so here we have

`P_1 = 7 * 10^5 Pa`

`T_1 = 273 + 21 = 294 k`

`T_2 = (273 + 35) = 308 k`

now we have

`(7 * 10^5)/(294) = (P_2)/(308)`

`P_2 = 7.33 * 10^5 Pa`