Two thirds of a number decreased by 27 is at least 9

Question

asked Oct 15, 2020 205k views

1 Answer

Inertiatic · Answer 1 · 2020-10-21T19:55:25+0000

Answer:

The mathematical statement can be written as follows

$(2)/(3)x-27\geq9$

which has solution as

⇒
$x\geq54$

Explanation:

Given:

Two thirds of a number decreased by 27 is at least 9.

This statement can be transformed into a mathematical statement.

Taking the unknown number as
and putting the inequality
$\geq9$ as the result is at least 9.

So, we have

$(2)/(3)x-27\geq9$

Adding 27 both sides

$(2)/(3)x-27+27\geq 9+27$

$(2)/(3)x\geq 36$

Multiplying both sides by 3.

$3*(2)/(3)x\geq 36* 3$

$2x\geq108$

Dividing both sides by 2.

$(2x)/(2)\geq(108)/(2)$

∴
$x\geq54$