Question

What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?

Answer 1

Answer:
`AlF_(3)`

Step-by-step explanation:

The chemical equation of the reaction that occurs when
`AlF_(3)` reacts with
`O_(2)` is

`4AlF_(3)+3O_(2)`→
`2Al_(2)O_(3)+6F_(2)`

`4` moles of
`AlF_(3)` requires
`3` moles of
`O_(2)`.

`1` mole of
`AlF_(3)` requires
`(3)/(4)` moles of
`O_(2)`.

Given that we have
`9` moles of
`AlF_(3)`.

`9` moles of
`AlF_(3)` requires
`(3)/(4)* 9=6.75` moles of
`O_(2)`.

But we have
`12` moles of
`O_(2)`.

So,
`AlF_(3)` will be consumed first.

So,
`AlF_(3)` is the limiting reagent.