Question

What is the concentration of a solution prepared by placing 20. mL of 0.12 M K2S in a graduated cylinder and pouring water until you reach the 100.0 mL mark (the final volume after mixing the solution with water is 100.0 mL).

Answer 1

Answer: 0.024 M

Step-by-step explanation:

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock solution = 0.12 M

`V_1` = volume of stock solution = 20.0 ml

`M_2` = molarity of diluted solution = ? M

`V_2` = volume of diluted solution = 100.0 ml

Putting in the values we get:

`0.12M* 20.0=M_2* 100.0`

`M_2=0.024`

Therefore, the concentration of the resulting solution is 0.024 M.