Question

calculate the eccentricity of jupiter's orbit if the aphelion is 816.62 million km and the perihelion is 741.52 million km

Answer 1

Answer:0.048

Step-by-step explanation:

Let the length of perihelion be
`p`

Let the length of aphelion be
`a`

Let the length of semi major axis of the elliptical path be
`s`

As we know that semi major axis is the average of perihelion and aphelion.

So,
`s=(p+a)/(2) =(1558.14)/(2)=779.07`
`millionKm`

Let the eccentricity of the elliptical path be
`e`

`e=1-(p)/(s)=1-(741.52)/(779.07)=0.048`