Question

What temperature change in Celsius degrees is produced when 800. J is absorbed by 100. G of water?

Answer 1

ΔT = 1.914 °C

Step-by-step explanation:

Given data:

Temperature change = ?

Heat absorbed = 800 j

Mass of water = 100 g

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = Q / m.c

ΔT = 800 j/ 100 g. 4.18 j/g.°C

ΔT = 800 j/ 418 j /.°C

ΔT = 1.914 °C