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In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002.
Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002?

asked
User Keidi
by
8.5k points

2 Answers

7 votes

Answer:

(3640-3250)/3250 x 100 = 3

/25'100 x

25

,

100

x

(390)/3250 x 100 = 12 x

.12 x 100 = 12.6%

Explanation:

answered
User Pavel Hlobil
by
7.7k points
3 votes

Hello!

The formula for percentage change is:

(New number - Original number) / Original number × 100 = Percentage change

(3640-3250)/3250 x 100 =

(390)/3250 x 100 =

.12 x 100 = 12%

(4100-3640)/3640 x 100 =

(460)/3640 x 100 =

.1263736264 x 100 = ~ 12.6%

2001 to 2002 had a higher percent of increase.

Hope I helped!!

answered
User Nhjk
by
8.7k points
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