Question

Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

Answer 1

The population of town after 1 year is 25,750 .

Explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population ×
`(1+(\textrm rate)/(100))^(\textrm n)`

Or, The population after 1 year = 25,000 ×
`(1+(\textrm 3)/(100))^(\textrm 1)`

Or, The population after 1 year = 25,000 ×
`(1.03)^(1)`

Or, The population after 1 year = 25,000 × 1.03

∴ The population after 1 year = 25,750

Hence The population of town after 1 year is 25,750 . Answer