asked 6.9k views
0 votes
Calculate the enthalpy change for the thermite reaction: 2Al(s)+Fe2O3(s)→2Fe(s)+Al2O3(s), ΔH∘rxn=−850 kJ when 10.0 mol of Al undergoes the reaction with a stoichiometrically equivalent amount of Fe2O3. Express your answer to three significant figures and include the appropriate units.

1 Answer

5 votes

Answer:

Enthalpy change when 10.0 moles of aluminium reacts with stoichiometrically equivalent ferric oxide is
-4.25* 10^(3) kJ.

Step-by-step explanation:


2Al(s)+Fe_2O_3(s)\rightarrow 2Fe(s)+Al_2O_3(s),\Delta H^o_(rxn)=-850 kJ

Energy change of the reaction when 2 mole of aluminium reacts with 1 mol of ferric oxide :
\Delta H^o_(rxn)=-850 kJ

Energy change of the reaction when 1 mole of aluminium reacts :


(\Delta H^o_(rxn))/(2)=(-850 kJ)/(2)=-425 kJ

Enthalpy change when 10.0 moles of aluminium reacts with stoichiometrically equivalent ferric oxide:


-425 kJ* 10.0 =-4250.0 kJ=-4.25* 10^(3) kJ

answered
User Srisudhir T
by
8.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.