Question

A student pulls on a 20kg box with a force of 50 N at an angle 45 degrees relative to the horizontal. The box increases speed at a rate of 1.5 m/s2. What is the approximate normal forc on the box

Answer 1

Answer:160.65 N

Step-by-step explanation:

Let
`F` be the force exerted by the student.

Let
`F_(v)` be the vertical component of force.

Let
`\alpha` be the angle between horizontal and direction of application of force.

Given,

`F=50N\\\alpha =45^(0)`

`F_(h)=Fcos\alpha =50* cos45=35.35N\\`

Let
`w` be the weight of the object.

Given mass of box=
`m=20Kg`

`w=mg=20* 9.8=196N`

Let
`N` be the normal force.

Since the vertical force from student is in opposite direction of that of weight of box,

`N=mg-F_(v)`

`N=196-35.35\\N=160.65Newtons`