Question

Solve the equation 4x^2+49=0​

Answer 1

x=7/2i, -7/2i

Explanation:

4x^2+49=0

4(x^2+49/4)=0

x^2+49/4=0/4

x^2+49/4=0

x^2=0-49/4

x^2=-49/4

take the square root of -49/4, you'll get imaginary numbers because of the negative sign.

x=7/2i, -7/2i