If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if …

Question

asked Feb 20, 2020 79.8k views

1 Answer

Inanc Gumus · Answer 1 · 2020-02-23T13:51:19+0000

Answer

Assuming

electric motor consumes = 9.00 k J

electrical energy for time = 1.00 min

speed of engine = 2500 rpm

Power =
$\tau_2\omega_2$

E = (2)/(3)* (P)

E = (2)/(3)* (9)

E = 6 k J

E = P t

P = (E)/(t)

$P = (6000 J)/(60\ s)$

P = 100 W

$\omega_2 = 2600 rpm = 2600 * (2\pi)/(60)$

$\omega_2 = 272\ rad/s$

$\tau_2 = (P)/(\omega_2)$

$\tau_2 = (100)/(272)$

τ₂ = 0.368 N.m