Question

Tripling a number n and adding ten gives a result that is two less than seven times n.

Find n.

Answer 1

The given equation from the problem can be solved algebraically to find that the number n is 3.

Step-by-step explanation:

Tripling a number n and adding ten gives a result that is two less than seven times n. To find n, we can set up the following algebraic equation based on the given conditions: 3n + 10 = 7n - 2.

Now, we will solve for n:

Subtract 3n from both sides: 10 = 4n - 2.

Add 2 to both sides: 12 = 4n.

Divide both sides by 4: n = 3.

Therefore, the number n is 3.

Answer 2

n = 3

Step-by-step explanation:

First we begin by setting up the equation. Tripling n and adding 10 looks like: 3n + 10. The result can be set up looking like 7n-2 since it is two less (-2) than seven times n (7n). Then we put it together in an equation:

3n+10 = 7n-2

+2 +2

3n+12 = 7n

-3n -3n

12 = 4n

/4 /4

3 = n or n = 3