Question

9. Water is added to two containers for 20 minutes. The equations below model the ounces of

water, y, in each container after x minutes. At the time when the containers hold the same
amount of water, how much water do they hold?
Container A: y = 62x+48
Container B: y=-2x^2+80x+120
234 ounces
482 ounces
792 ounces
920 ounces

Answer 1

792 pounds

Explanation:

Answer 2

792 ounces

Explanation:

The equations below model the ounces of water, y, in each container after x minutes.

Container A: y = 62x + 48

Container B: y = -2x² + 80x + 120

Now, at a time when both the containers hold the same amount of water, is given by

62x + 48 = -2x² + 80x + 120

⇒ 2x² - 18x - 72 = 0

⇒ x² - 9x - 36 = 0

⇒ x² - 12x + 3x - 36 = 0

⇒ (x - 12)(x + 3) = 0

Hence, x = 12 or - 3.

But x can not be negative.

So, x = 12 minutes.

Therefore, after 12 minutes both the container will have the same amount of water and the quantity is = 62 × 12 + 48 = 792 ounces. (Answer)