Question

Given the E0 values of the following two half-reactions: Zn  Zn2+ + 2e- E0 = 0.763 volt Fe  Fe2+ + 2e- E0 = 0.441 volt a) Write a balanced complete oxidation-reduction reaction? b) Explain whether the corrosion of an iron pipe (i.e., Fe  Fe2+) in the presence of Zn/Zn2+ is possible or not (thermodynamically)? c) Explain whether or not Zn will protect the corrosion of iron pipe if metallic Zn is in contact with the iron pipe?

Answer 1

For a: The balanced chemical equation is written below.

For b: The corrosion of iron pipe will take place in the presence of zinc.

For c: Zinc will not protect iron pipe from corrosion.

Step-by-step explanation:

• For a:

The given half reaction follows:

The substance having highest positive
`E^o` potential will always get reduced and will undergo reduction reaction. Here, zinc will undergo reduction reaction will get reduced.

Oxidation half reaction:
`Zn\rightarrow Zn^(2+)+2e^-;E^o_(Zn^(2+)/Zn)=-0.763V`

Reduction half reaction:
`Fe+2e^-\rightarrow Fe;E^o_(Fe^(2+)/Fe)=-0.441V`

The balanced chemical equation follows:

`Fe+Zn^(2+)\rightarrow Fe^(2+)+Zn`

• For b:

For a reaction to be spontaneous (thermodynamically feasible) , the standard electrode potential must be positive.

To calculate the
`E^o_(cell)` of the reaction, we use the equation:

`E^o_(cell)=E^o_(cathode)-E^o_(anode)`

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Calculating the
`E^o_(cell)` using above equation, we get:

`E^o_(cell)=-0.441-(-0.763)=0.322V`

As, the EMF is coming out to be positive, the reaction will be thermodynamically feasible and corrosion of iron pipe will take place in the presence of zinc.

• For c:

As, the EMF of the cell is positive, the zinc will not protect the iron pipe from corrosion and the reaction will take place.