Question

What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x/3−1 ?

Answer 1

y = -3x + 14

Explanation:

y=x/3−1

The slope of the perpendicular line is the reciprocal of the given equation.

Given is 1/3x. Perpendicular slope is m=-3x

Substitute the perpendicular slope and the point (4,2) in an equation

y = mx + b

2 = -3(4) + b

2 = -12 + b

Find b by isolating

b = 2+12

b = 14

Substitute the slope -3x and b=14 to find the equation of the line.

y = mx + b

y = -3x + 14