Question

9.10 raised to seven is how many times as large as 3. 10 raised to negative 2

Answer 1

49,660,733.96

Explanation:

Required to Find

How many times is
`9.1^(7)` greater than
`3.1^(-2)`

⇒

To find the required factor ,we have to divide the numbers

⇒The required number

`=(9.1^(7) )/(3.1^(-2) ) =9.1^(7) *3.1^(2) =5167610.19 * 9.21=49660733.96`