Question

What is the equation in point slope from a line that goes through eight -4 and has a slope of negative 5/6

Answer 1

`\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{-4})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{5}{6} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{\cfrac{5}{6}}(x-\stackrel{x_1}{8})\implies y+4=\cfrac{5}{6}(x-8)`