What is the percentage of a mixture containing 2.5lb of salt and 4 gallons of water

Question

asked Jan 6, 2020 14.0k views

1 Answer

Techneaz · Answer 1 · 2020-01-11T17:37:33+0000

Answer:

Percentage of mixture=
$7.5\%$

Explanation:

Salt content in pounds=
2.5 lb

$1\ lb = 0.12\ gal$

Therefore salt content in gallons =
2.5* 0.12 = 0.3 gal

Water content in mixture =
gal

Percentage of mixture=
$(\ Salt\ Content)/(Water\ Content)* 100 = (0.3)/(4)* 100=(30)/(4)=7.5\%$