A well-designed boiler evaporates 8.5 pounds of water per pound of coal burned. find how many pounds of coal would be necessary to evaporate 68 pounds of water.

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asked Feb 15, 2020 227k views

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EdJoJob · Answer 1 · 2020-02-21T16:03:00+0000

Answer:
8
Step-by-step explanation:
8.5 Per 1 pound can be written as 8.5/1
8.5/1 = 68/? . To find the kissing component you must do 8.5 divided by 68. That should be 8

A well-designed boiler evaporates 8.5 pounds of water per pound of coal burned. find how many pounds of coal would be necessary to evaporate 68 pounds of water.

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A well-designed boiler evaporates 8.5 pounds of water per pound of coal burned. find how many pounds of coal would be necessary to evaporate 68 pounds of water.​

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A well-designed boiler evaporates 8.5 pounds of water per pound of coal burned. find how many pounds of coal would be necessary to evaporate 68 pounds of water.