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Of 201 adults selected randomly from one town, 179 have credit cards. Find a 90% confidence interval for the true proportion of all adults in the town who have credit cards.​

Of 201 adults selected randomly from one town, 179 have credit cards. Find a 90% confidence interval for the true proportion of all adults in the town who have credit cards.​
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Of 201 adults selected randomly from one town, 179 have credit cards. Find a 90% confidence interval for the true proportion of all adults in the town who have credit cards.​

asked
User Robert Gummesson
by
8.8k points

1 Answer

1 vote

Answer:

I think this is a probability problem.

Explanation:

201*0.9 the divide by 179??

answered
User Avloss
by
8.2k points
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