Question

When the volume of a gas is

changed from 4.51 L to _L, the
temperature will change from 0.00°C
to 273°C.

Answer 1

V₂ = 9.02 L

Step-by-step explanation:

Given data:

Initial volume = 4.51 L

Initial temperature = 0°C ( 273 k)

Final temperature = 273 °C (273+273 = 546 K)

Final volume = ?

Solution:

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 4.51 L×546 K / 273 k

V₂ = 2462.46 L /273

V₂ = 9.02 L