asked 214k views
5 votes
If y = f(x) = 2(4)x + c, find the value of "c" that results in a graph with x-intercept at (2, 0).

A) −32
B) −8
C) 32
D) 8

asked
User Lerato
by
8.6k points

1 Answer

0 votes

Answer:

Option A) −32

Explanation:

we have


f(x)=2(4)^(x)+C

we know that

For x=2, f(x)=0 ----> given problem

so

substitute the value of x and the value of f(x) in the function above and solve for C


0=2(4)^(2)+C


0=2(16)+C


0=32+C


C=-32

answered
User Jowayne
by
8.0k points
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