Question

If the enzyme molecule has more than one active site, then [E]t is multiplied by the number of active sites to determine its effective concentration. Determine the value of the turnover number of the enzyme carbonic anhydrase, given that ????max for carbonic anhydrase equals 249 μmol⋅L−1⋅s−1 and [E]t=2.20 nmol⋅L−1 . Carbonic anhydrase has a single active site. turnover number =

Answer 1

The value of the turnover number of the enzyme carbonic anhydrase is
`1.1318* 10^5 s^(-1)`.

Step-by-step explanation:

The turnover number is defined as maximum number of conversions of substrate molecules per second by a single catalytic site for given a concentration of enzyme..

Turn over number =
`(R_(max))/([E]_t)`

`[E]_t`=catalytic site concentration

`R_(max)`= Maximum reaction rate

We are given with:

`R_(max)=249 \mu mol/L s=24* 10^(-6) mol/L s`

`[E]_t=2.20 nmol/L=2.20* 10^(-9) mol/L`

Turnover number :

=
`(249* 10^(-6) mol/L s)/(2.20* 10^(-9) mol/L)=1.1318* 10^5 s^(-1)`

The value of the turnover number of the enzyme carbonic anhydrase is
`1.1318* 10^5 s^(-1)`.