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In which one of the following processes is ΔH = ΔE? A. 2HI(g) => H2(g) + I2(g) at atmospheric pressure. B. Two moles of ammonia gas are cooled from 325 ?°C to 300 °C at 1.2 atm. C. H2O(l) => H2O(g) at 100 °C at atmospheric pressure. D. CaCO3(s) => CaO(s) + CO2(g) at 800 °C at atmospheric pressure. E. CO2(s) => CO2(g) at atmospheric pressure.

1 Answer

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Answer : Only option A shows
\Delta H=\Delta E

Explanation :

Formula used :


\Delta H=\Delta E+\Delta n_gRT


\Delta H = change in enthalpy


\Delta E = change in internal energy


\Delta n_g = change in moles

R = gas constant = 8.314 J/mol.K

T = temperature

According to the question,
\Delta H=\Delta E when the value of
\Delta n_gRT will be zero.

Now we have to determine the value of
\Delta n_gRT for the following cases.

(A)
2HI(g)\rightarrow H_2(g)+I_2(g) at atmospheric pressure.

In this case:


\Delta n_g = change in moles

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = (1+1) - 2 = 2 - 2 = 0 mole

That means, value of
\Delta n_gRT = 0

So, in this process
\Delta H=\Delta E

(B) Two moles of ammonia gas are cooled from 325 °C to 300 °C at 1.2 atm.

In this case:


\Delta n_g = change in moles = 2

That means, value of
\Delta n_gRT ≠ 0

So, in this process
\Delta H\\eq \Delta E

(C)
H_2O(l)\rightarrow H_2O(g) at 100 °C at atmospheric pressure.

In this case:

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 1 - 0 = 1 mole


\Delta n_g = change in moles = 1

That means, value of
\Delta n_gRT ≠ 0

So, in this process
\Delta H\\eq \Delta E

(D)
CaCO_3(s)\rightarrow CaO(s)+CO_2(g) at 800 °C at atmospheric pressure.

In this case:

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 1 - 0 = 1 mole


\Delta n_g = change in moles = 1

That means, value of
\Delta n_gRT ≠ 0

So, in this process
\Delta H\\eq \Delta E

(E)
CO_2(s)\rightarrow CO_2(g) at atmospheric pressure.

In this case:

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 1 - 0 = 1 mole


\Delta n_g = change in moles = 1

That means, value of
\Delta n_gRT ≠ 0

So, in this process
\Delta H\\eq \Delta E

Hence, from this we conclude that, only option A shows
\Delta H=\Delta E

answered
User Rob Audenaerde
by
7.9k points
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