Question

How many moles of ZnCl, will be produced from 23.0 g of Zn, assuming CuCl, is available in excess?

Answer 1

23 g of Zn will produce 0.352 mole of zinc chloride.

Step-by-step explanation:

Given data:

mass of Zn = 23 g

Moles of ZnCl = ?

Solution:

Chemical equation:

2Zn + CuCl₂ → 2ZnCl + Cu

Number of moles of Zn:

Number of moles of Zn = mass/ molar mass

Number of moles of Zn = 23 g / 65.38 g/mol

Number of moles of Zn = 0.352 mol

now we will compare the moles of ZnCl with Zn because it is limiting reactant.

Zn : ZnCl

2 : 2

0.352 : 0.352

So 23 g of Zn will produce 0.352 mole of zinc chloride.