Question

How many grams of Sodium hydroxide are present in 750.0 mL of 2.5 M sodium hydroxide solution?

Answer 1

75 g of sodium hydroxide is present in the solution.

Step-by-step explanation :

Given :

Molarity of sodium hydroxide solution= 2.5 M

Litres of Solution = 750 mL

Molar mass of NaOH = 40 g/mol

To Find:

Grams of Sodium Hydroxide =?

Solution :

Molarity of the solution is expressed in Litres, So Converting 750.0 mL to Litres we have

750.0mL=0.750 Litres

Grams of Solution , moles=
`M* L`

Where

M = Molarity

L = litres of solution

mol= moles of solute

`mol= 2.5 * (750)/(1000)`

Mol = 1.875

Also the molecular weight of NaOH is 40.00 g/mol

Grams of sodium hydroxide = 1.875 mol * 40.00 g/mol = 75 g