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3n - 7 > n + 1 or 4n - 5 < 3n - 3

asked
User Delton
by
8.5k points

1 Answer

1 vote

Answer:

n > 4

Step-by-step explanation:

3n - 7 > n + 1

Move variable to the left side and change its sign

3n - n - 7 > 1

...

3n - 7 > n + 1

Move constant to the right side and change its sign

3n - n > 1 + 7

...

3n - n > 1 + 7

Collect the like terms

2n < 1 + 7

...

3n - n > 1 + 7

Add the numbers

2n < 8

Divide both sides of the inequality by 2

Solution:

n > 4 Answer:

n < 2

Explanation:

4n - 5 < 3n - 3

Move variable to the left side and change its sign

4n - 3n - 5 < - 3

...

4n - 5 < 3n -3

Move constant to the right side and change its sign

4n - 3n < - 3 + 5

...

4n - 3n < - 3 + 5

Collect the like terms

n < - 3 + 5

...

4n - 3n < - 3 + 5

Calculate the sum

n < 2

...

Solution:

n < 2

answered
User Cheknov
by
8.4k points

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