Question

Please HElp!! What is the equation of a circle with its center at (−6,−3) and a radius of 12? `

(x+6)2+(y+3)2=144
(x−6)2+(y−3)2=12
(x−6)2+(y−3)2=144
(x+6)2+(y+3)2=12
(x+6)2+(y+3)2=24

Answer 1

Given the center (a,b) and the radius r, the equation of the circle is

`(x-a)^2+(y-b)^2=r^2`

Plug your values a = -6, b = -3, r = 12

`(x+6)^2+(y+3)^2=144`