Answer:
528.086 atm
Step-by-step explanation:
We are given;
The number of moles of an ideal gas as 3.6 moles
Volume occupied by the gas is 150 mL or 0.15 L
Temperature of the gas is -5° C
But, K = °C + 273.15
Therefore, Temperature, T = 268.15 K
We are required to calculate the pressure in the tank.
In this case we are going to use the ideal gas equation;
- The ideal gas equation states, PV = nRT, where P is the pressure, v is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant, 0.082057 L.atm/mol.K
- Therefore, rearranging the equation we can find the pressure in the tank.
P = nRT÷ V
= (3.6 mole × 0.082057 × 268.15 K)÷ 0.15 L
=528.086 atm
Therefore, the pressure in the tank is 528.086 atm