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Find two numbers whose sum is 18 who’s difference is 22

2 Answers

3 votes

Final answer:

To find two numbers whose sum is 18 and whose difference is 22, we can set up a system of equations and solve for the unknown variables.

Step-by-step explanation:

To find two numbers whose sum is 18 and whose difference is 22, we can set up a system of equations.

Let's call the two numbers x and y.

We have the following equations:

  1. x + y = 18
  2. x - y = 22

We can solve this system of equations by elimination or substitution. Using substitution, we can solve the second equation for x and substitute it into the first equation:

  1. x = 22 + y
  2. (22 + y) + y = 18
  3. 2y + 22 = 18
  4. 2y = 18 - 22
  5. 2y = -4
  6. y = -2

Now that we have the value of y, we can substitute it back into the first equation to find x:

  1. x + (-2) = 18
  2. x = 18 + 2
  3. x = 20

Therefore, the two numbers are 20 and -2.

answered
User Simone Colnaghi
by
7.9k points
4 votes

Answer:

The Answer is: The first number is 20 and the second number is -2.

Step-by-step explanation:

Let f = first number and s = second number.

The sum is 18:

f + s = 18

Solve for s:

s = 18 - f

The difference is 22:

f - s = 22

Substitute:

f - (18 - f) = 22

f - 18 + f = 22

2f = 22 + 18

2f = 40

f = 20, the first number.

Solve for s:

s = 18 - f

s = 18 - 20 = -2, the second number.

Proof:

20 + (-2) = 18

20 - 2 = 18

18 = 18

Then:

f - s = 22

20 - (-2) = 22

20 + 2 = 22

22 = 22

Hope this helps! Have an Awesome Day!! :-)

answered
User Andrey Izotov
by
8.9k points

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