Question

What are 5 consecutive odd integers of 445

Answer 1

87,88,89,90,91,92

Explanation:

to find the answer to this math problem you set up the equation like this:

x+x+1+x+2+x+3+x+4=445

then combine like terms:

5x+10=445

then solve

5x+10=445

-10 -10

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5x=435

then divide both sides by 5

x=87

and because there are 5 consecutive terms...

87,88,89,90,91,92