Question

1. The area of a square with side length x, where the side length is decreased by 3, the area is

multiplied by 2 and then 4 square units are added to the area.​

Answer 1

`2x^2-12x+22`

Explanation:

Let's follow what the problem asks us:

• "The area of a square with side length x"

this is the formula for area:
`area=side*side=side^2`

since the side length is x, the initial area is:
`x^2`

• Now, "where the side length is decreased by 3":

The side is now
`(x-3)`, thus the area is:
`(x-3)^2=x^2-6x+9`

• "the area is multiplied by 2"

we had the area
`x^2-6x+9`, when we multiply by 2:

`(2)(x^2-6x+9)=2x^2-12x+18`

• And finally " then 4 square units are added to the area.​"

this is:
`2x^2-12x+18 + 4=2x^2-12x+22`