Question

A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the horizontal. The frictional coefficients between the crate and plane are (\muμs = 0.84, \muμk = 0.48 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?

Answer 1

a = 8.951 m/s²

Step-by-step explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F + f = m a

mg sin θ + μk mg cos θ = m a

a = g sin θ + μk g cos θ

a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²