Answer:
78.34 g
Step-by-step explanation:
From the question we are given;
Moles of Nitrogen gas as 2.3 moles
we are required to calculate the mass of NH₃ that may be reproduced.
Step 1: Writing the balanced equation for the reaction
The Balanced equation for the reaction is;
N₂(g) + 3H₂(g) → 2NH₃(g)
Step 2: Calculating the number of moles of NH₃
From the equation 1 mole of nitrogen gas reacts to produce 2 moles of NH₃
Therefore, the mole ratio of N₂ to NH₃ is 1 : 2
Thus, Moles of NH₃ = Moles of N₂ × 2
= 2.3 moles × 2
= 4.6 moles
Step 3: Calculating the mass of ammonia produced
Mass = Moles × molar mass
Molar mass of ammonia gas = 17.031 g/mol
Therefore;
Mass = 4.6 moles × 17.031 g/mol
= 78.3426 g
= 78.34 g
Thus, the mass of NH₃ produced is 78.34 g