Question

Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon. What fractional part of a gallon of limeade remained in the pitcher?

Answer 1

2/5

Explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk =
`(1)/(4) +(1)/(8)` =
`(3)/(8)`

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained =
`(5)/(8) -(3)/(8)` =
`(1)/(4)`

Fractional part = amount remained / amount initially =
`((1)/(4) )/((5)/(8) )` =
`(2)/(5)`