Question

Name and draw the structure of the simplest hydrocarbon that contains at least one primary, one secondary, and one tertiary position in the same molecule. Give the total number of possible monochlorinated products (all possible constitutional isomers and stereoisomers) that could be obtained from the free radical chlorination of this compound give the structure of all the monochlorinated products

Answer 1

The compound will be: 2,2-dimethylbutane

The total number of possible isomer of mono chlorinated product will be: four

Step-by-step explanation:

Primary carbon is one which has three hydrogens

Secondary carbon is one which is directly attached to two carbons

Tertiary carbon is one which is directly attached to three carbons

The compound will be: 2,2-dimethylbutane

The total number of possible isomer of mono chlorinated product will be: four