Question

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

Answer 1

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is
`\left((-9)/(2), (-3)/(2)\right)`

Solution:

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by
`\left(\mathrm{x}_(1), \mathrm{y}_(1)\right) \text { and }\left(\mathrm{x}_(2), \mathrm{y}_(2)\right)` is given by:

`\text { Mid point } \mathrm{m}=\left((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2)\right)`

`\text { Here in our problem, } x_(1)=-6, y_(1)=6, x_(2)=-3 \text { and } y_(2)=-9`

Plugging in the values in formula, we get,

`\begin{array}{l}{m=\left((-6+(-3))/(2), (6+(-9))/(2)\right)=\left((-6-3)/(2), (6-9)/(2)\right)} \\\\ {=\left((-9)/(2), (-3)/(2)\right)}\end{array}`

Hence, the midpoint of the segment is
`\left((-9)/(2), (-3)/(2)\right)`