Question

If a 1.00-L container was rated to withstand pressures up to 25.0 atm, calculate what the temperature must have been when it ruptured. The final volume of the gas at 1.00 atm and 30°C was 55.0 L

a. 394°C

b. 667°C

c. No right choice.

Answer 1

C. No right choice

Step-by-step explanation:

Using the gas equation:

V₁ P₁/T₁ =V₂ P₂/T₂------------------------------------- (1)

V₁= 1.00L

P₁= 25.0 atm

T₁= ?

V₂ = 55.0L

P₂ = 1.00 atm

T₂= 30°C

= 303°K

Making T₁ in equation (1) subject of the formula;

T₁=(V₁ P₁/V₂ P₂)x T₂------------------------------------ (2)

Substituting into equation (2), we have:

T₁ = [(1 x 25) / (55 x 1)] x 303

= 137.7° K

= -135.27 ° C