Question

Find the dy/dx

y = 2 sin x cos x​

Answer 1

y = 2 sin x cos x

dy/dx =

2[sin x . d (cos x)/dx + cos x . d(sin x)/dx]

dy/dx = y' =

2[ sin x . (-sin x) + cos x . cos x]

y' = 2 [cos² x - sin² x]

y' = 2 cos 2x [cos²x - sin²x = cos 2x]

Hence, option C is correct!

Hope it helps...!!